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Conor McGregor hits back at Joe Rogan on steroid use

Conor McGregor is not too happy with the accusations Joe Rogan made about him on a recent episode of his JRE podcast.

McGregor took to Twitter to vent his frustrations, putting the UFC color commentator on blast for suggesting that he's been utilizing performance-enhancing drugs.

In a now-deleted tweet, the Irishman included a photo comparing Rogan's physique at 25 years old to his physique at the age of 52. McGregor flipped the script on Rogan's steroid accusations, whilst also pointing out that that the stand-up comedian and podcaster has never fought in the octagon:

"Joe looks like his p*ss melts his knickers, in the company that long and never took a fight hahaha @ufc oh tae kwon do competition , call the cops hahahahaah"
Conor McGregor's now deleted tweet firing back at Joe Rogan - (@TheNotoriousMMA - Twitter)
Conor McGregor's now deleted tweet firing back at Joe Rogan - (@TheNotoriousMMA - Twitter)

Joe Rogan accuses Conor McGregor of using a USADA loophole

Despite Rogan not saying which specific PED he believes the former two-division UFC champion is taking, he did imply that as being the primary reason why McGregor removed himself from the USADA testing pool.

During an episode of his podcast, the longtime UFC color commentator said:

"He's taking his shirt off and posing constantly, and he looks like his p*ss would melt that USADA cup. Like it would just like burn a hole right to the bottom of that USADA cup...The weird thing is that there is a loophole in USADA that allows you to get out of the testing pool. It seems weird and you just need six months."
Joe Rogan believes Conor McGregor's urine contains enough steroids to burn a hole through the USADA test Cup 💉💪

Full story: sportskeeda.com/mma/news-joe-r…

#UFC #MMA https://t.co/B4z1McVOS0

McGregor has been actively stirring up the pot on Twitter as of late, targeting both Dustin Poirier and Nate Diaz as well. It will be interesting to see whether Rogan responds, or if cooler heads will prevail between the two.

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