Panpayak wants another crazy knockout over Silviu Vitez: “I’m so motivated now”
Thai star Panpayak Jitmuangnon wants to etch his name in the history book with another knockout victory in his next performance.
Slated to return in a clash with Silviu Vitez at ONE Friday Fights 83 on Oct 18, the 7x Muay Thai world champion believes he will be able to knock his opponent out when the time comes, just like he did with Michael Savvas.
In an interview with South China Morning Post, he described his extra motivation to create an unforgettable ending for the fans.
Moreover, if he can overrun Vitez, it will also increase his bid towards the top five ranks and, finally, the ONE flyweight Muay Thai world title contention.
The Jitmuangnon Gym representative said:
"I’m so motivated now, and I want to produce more fights like that [with Savvas]."
He continued:
"I promise to try everything I can to do that and to get more bonus as well when I put on a show for everybody."
With such conviction, it is certain that fans will be entertained with a barnburner clash when he faces Vitez in the near future.
Check out his full interview below:
Panpayak wants to stop Superlek's superhuman streak
Although suffering defeat at the hands of Superlek Kiatmoo9, Panpayak Jitmuangnon still thinks he would be the one who can stop the Thai superstar.
In his latest run at ONE 168: Denver, Superlek proved himself as one of the best strikers in the world by taking out Jonathan Haggerty in 49 seconds.
And, as a seven-time Muay Thai champion, Panpayak sees himself as a figure who can stop this superhuman winning streak, as he told South China Morning Post in an interview:
“I am the only one who can stop Superlek, just give me time.”
Clearly, he can be a dangerous striker with the skills to potentially take out Superlek.
While waiting for 'The Angel Warrior' at ONE Friday Fights 83, fans in the United States and Canada can watch the replay of ONE 168: Denver on demand with an active Amazon Prime Video subscription.
Watch Panpayak's last fight with Superlek below: